Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teams What causes a TypeError: unhashable type: ‘dict_keys’? A TypeError: unhashable type: ‘dict_keys’ occurs when you try to use a dictionary key as a hashable value. A hashable value is a value that can be used as the key in a dictionary. Dictionaries use hashable values to quickly find and access their data I then attempt to use the dict (each item from ‘results’ is itself a dict) as a key into that same dict. A dict is not a valid key; it is not a “hashable type” i.e. a type with a fixed value, that can produce a hash of the value). So I was getting dicts and attempting to use those dicts as keys into dicts You're trying to use a dict as a key to another dict or in a set. That does not work because the keys have to be hashable. As a. Skip to content >>> some_dict[dict_key] = True Traceback (most recent call last): File "", line 1, in TypeError: unhashable type: 'dict' To use a dict as a key you need to turn it into something 1 longitude name neighborhood postal_code \ 1 Kenzo Ramen Downtown Core M4Y 1X9 2 Vince Seafood Restaurant & BBQ Milliken L3R 6E4 3 Motorino Enoteca Pine Grove L4L 1A5 4 Northwood Bickford Park M6G 1M1 review_count stars_y state good_reviews 1 76 It gives you a TypeError, when you are trying to use d1 as a key, because keys can only be of hashable types. You can't use dict as a key in another dict, unless it is a custom class dict where the __hash__ method is defined. As it was said, this will do: for item in (d1,d2): [HOST](item) print(d3)
Unhashable type: 'ReturnDict' drf django - Stack Overflow
1 Answer. Sorted by: 1. You are using list as an key in the dictionary. List is not a hashable type in python. So, it can not be used as key in the dictionary. Only hashable types such as tuple, strings, numbers can be used as key in the dictionary. Share. Improve this answer How to overcome TypeError: unhashable type: 'list' [duplicate] Ask Question. Asked 11 years, 3 months ago. Modified 2 months ago. Viewed k times. This question Missing: dict grove NetworkX errors while adding nodes: "unhashable type: 'dict'" and "ValueError: too many values to unpack (expected 2)" 0 networkx and dict_values causing float argument error The Python TypeError: unhashable type: 'dict' usually occurs when trying to hash a dictionary, which is an unhashable object. For example, using a dictionary Missing: dict grove Error: unhashable type: 'dict' with @dataclass. name: str. signature: Dict[str, Type[DBType]] prinmary_key: str. foreign_keys: Dict[str, Type[ForeignKey]] indexed: List[str] Don't understand what's the problem. frozen=True prevents you from assigning new values to the attributes; it does not prevent you from mutating the existing mutable values To resolve this error, you need to make sure that you’re using a hashable type as the key in a dictionary object. If you need to add a value from another dictionary, Missing: dict grove Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teams TypeError: unhashable type: 'list' for comparing pandas columns. 4. How can I merge rows in pandas Dataframes when the value of a cell in a particular column is same. 0. Pandas dataframe: drop_duplicates after converting to str
Overcoming ‘TypeError: unhashable type: ‘dict” in Python
1 Answer. When you attempt to use (args,kwargs) as key (or part of the key) in cache [ (args,kwargs)], kwargs is of dict type. dict types are not able to be used as keys in dictionaries. In fact, no mutable data structures can be used as keys in dictionaries. An alternative is to use tuple ([HOST] ()) as this part of the key in the cache Dictionaries, sets, lists, and Series are mutable and, therefore, cannot be hashed. Conversely, numeric types, booleans, and strings are immutable, so they can all be hashed. Tuples are also immutable but can only be hashed if their elements and subelements are also immutable The variable v in this expression: key, v = spl [0], spl [1:] is a list with the remaining values. You cannot use a list to index a dictionary, so this: del dic [v] will fail. Looking at the code logic, you probably want to do this anyway: for For your case you can simply do: tmp1 = tmp[list(tmp)[0]] However this can be quite expensive. If all you need is any element from the dictionary then you could do: tmp1 = tmp[next(iter(tmp))] which avoids the cost of constructing the key list. Share 1 print(hash(dictionary)) TypeError: unhashable type: 'dict'. The code prints out the type to confirm the dictionary object is a ‘dict’ object. When we try to print the dictionary’s Missing: dict grove TypeError: unhashable type: '[HOST]y'. From a text file containing three columns of data I want to be able to just take a slice of data from all three columns where the values in the first column are equal to the values defined in above. I then want to put the slice of data into a new array called slice (I am using Python ) TypeError: unhashable type: 'dict' Related. How to convert Counter object to dict? TypeError: unhashable type: 'dict' 9. Python3: TypeError: unhashable type: 'list' when using Counter. 1. Python counter not recognizing dictionary. 0. Count mismatching while using dictionary in python. 1 TypeError: unhashable type: 'dict'. for code in compressed: if not (code in dictionary): dictionary[code] = string + (string[0]) decompressed_data += Missing: dict grove