A rhombus has four sides of equal lengths. It has two pairs of equal angles. The opposite sides are parallel. The diagonals bisect each other at right angles I'm stuck on trying to provide a proof in relation to: "prove that the diagonals of a rhombus bisect the angle of the rhombus using vector methods." I'm unsure what
Rhombus diagonals (video) | Quadrilaterals | Khan Academy
The diagonals of a rhombus are perpendicular, they cross at right angles. When the diagonals of a rhombus are equal the rhombus becomes a square. The diagonals of a rhombus bisect Mathematically, this can be represented as, Area of rhombus = 4 × area of one triangle Area of rhombus = 4 × (1/2 × base × height). Now, if we take the diagonals of the
Vector Proof of Diagonals of a Rhombus - Mathematics Stack Exchange
Video transcript. I want to do a quick argument, or proof, as to why the diagonals of a rhombus are perpendicular. So remember, a rhombus is just a parallelogram where Q. Prove that in a rhombus, the diagonals are perpendicular to each other. Q. Prove that the diagonals of a rhombus are perpendicular bisectors of each other. Q. Prove that, if the diagonals of a parallelogram are perpendicular to each other, the parallelogram is a rhombus Some properties of diagonals. A parallelogram is a quadrilateral whose diagonals bisect each other. A rhombus is a parallelogram whose diagonals are perpendicular. A 2) Perpendicular Diagonals: They are diagonals that intersect each other at right angles (90°). In other words, perpendicular diagonals form four right angles at the